Talk:Composing

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Revision as of 06:37, 2 January 2014 by CALLmeABC (Talk | contribs)

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Lets try to figure out how the XP earned works ... first we need to collect some data:

Amount of Buffs Level Buffs Time (mins) XP
1 150 30 10
1 150 60 20
1 150 120 30 (confirmed)
2 150 30 20
1 10 30 10
2 10 60 10 (retry please)
1 10 300 10
2 100 30 10
2 150 300 60
2 150 120 30 (confirmed)
1 60 60 20 (retry)

270mins, 270skill points = 60XP (retry)

possible formulas:

  • total buff level to calculate XP?
    • if below x always 10XP?
  • multiplied by duration factor?


As Hoof stated in the forums (http://forums.huntedcow.com/index.php?showtopic=58448&page=10#entry810636)

  • composingXPGained = ceil((durationFactor / 60) + (totalPotionSkillLevel / 500)) * 10


ojo1 understood it like this


That's correct, ojo1. The updated formula should look like this:

  • composingXPGained = ceil((min(durationFactor, totalPotionSkillLevel) / 60) + (totalPotionSkillLevel / 500)) * 10

--Majere 16:15 8 September 2013 (UTC)

Leveling with the least amount of commons

This is my first ever time controubiuting in any way to any form of wiki- If the forulma fo getting the optioum XP for the leaset amount of fragments were to be updated to use a base of 50 instead of a base of 50 it would save a lot of people a lot of fragments and be a little more accurate to it's name.

For example :A potition brewed with 4 level 50 skill and 1 level 68 skill for 160 common and 10 rare to get 60 XP The one on the guide proposes 4 level 40 and 1 level 108 for 126 common and 27 rare to get 60

Another example is the 50 XP potion, 5 level 45 skills only need 150 common and you get 50 xp, no rare required