Talk:Composing

Lets try to figure out how the XP earned works ... first we need to collect some data:

Amount of Buffs	Level Buffs	Time (mins)	XP
1	150	30	10
1	150	60	20
1	150	120	30 (confirmed)
2	150	30	20
1	10	30	10
2	10	60	10 (retry please)
1	10	300	10
2	100	30	10
2	150	300	60
2	150	120	30 (confirmed)
1	60	60	20 (retry)

270mins, 270skill points = 60XP (retry)

possible formulas:

• total buff level to calculate XP?
  • if below x always 10XP?
• multiplied by duration factor?

As Hoof stated in the forums (http://forums.huntedcow.com/index.php?showtopic=58448&page=10#entry810636)

• composingXPGained = ceil((durationFactor / 60) + (totalPotionSkillLevel / 500)) * 10

ojo1 understood it like this

• http://www.wolframalpha.com/input/?i=ceil%28%28DURATION+%2F+60%29+%2B+%28+TOTAL+SKILL+LEVEL%2F+500%29%29+*+10 , just replace "DURATION" for the duration of the pot (30, 60, 120, etc.) and "TOTAL SKILL LEVEL" for the total of the skills level
  • note if the DURATION is bigger than TOTAL SKILL LEVEL, use the same number from TOTAL SKILL LEVEL for the DURATION

That's correct, ojo1. The updated formula should look like this:

• composingXPGained = ceil((min(durationFactor, totalPotionSkillLevel) / 60) + (totalPotionSkillLevel / 500)) * 10

--Majere 16:15 8 September 2013 (UTC)

Leveling with the least amount of commons

This is my first ever time controubiuting in any way to any form of wiki- If the forulma fo getting the optioum XP for the leaset amount of fragments were to be updated to use a base of 50 instead of a base of 50 it would save a lot of people a lot of fragments and be a little more accurate to it's name.

For example :A potition brewed with 4 level 50 skill and 1 level 68 skill for 160 common and 10 rare to get 60 XP The one on the guide proposes 4 level 40 and 1 level 108 for 126 common and 27 rare to get 60

Another example is the 50 XP potion, 5 level 45 skills only need 150 common and you get 50 xp, no rare required